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9x-10=9/x
We move all terms to the left:
9x-10-(9/x)=0
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
9x-(+9/x)-10=0
We get rid of parentheses
9x-9/x-10=0
We multiply all the terms by the denominator
9x*x-10*x-9=0
We add all the numbers together, and all the variables
-10x+9x*x-9=0
Wy multiply elements
9x^2-10x-9=0
a = 9; b = -10; c = -9;
Δ = b2-4ac
Δ = -102-4·9·(-9)
Δ = 424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{424}=\sqrt{4*106}=\sqrt{4}*\sqrt{106}=2\sqrt{106}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{106}}{2*9}=\frac{10-2\sqrt{106}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{106}}{2*9}=\frac{10+2\sqrt{106}}{18} $
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