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9x-16=3(2x-6)+3x+2
We move all terms to the left:
9x-16-(3(2x-6)+3x+2)=0
We calculate terms in parentheses: -(3(2x-6)+3x+2), so:We get rid of parentheses
3(2x-6)+3x+2
We add all the numbers together, and all the variables
3x+3(2x-6)+2
We multiply parentheses
3x+6x-18+2
We add all the numbers together, and all the variables
9x-16
Back to the equation:
-(9x-16)
9x-9x+16-16=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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