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9x-1=5-(x2)
We move all terms to the left:
9x-1-(5-(x2))=0
We add all the numbers together, and all the variables
-(-1x^2+5)+9x-1=0
We get rid of parentheses
1x^2+9x-5-1=0
We add all the numbers together, and all the variables
x^2+9x-6=0
a = 1; b = 9; c = -6;
Δ = b2-4ac
Δ = 92-4·1·(-6)
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{105}}{2*1}=\frac{-9-\sqrt{105}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{105}}{2*1}=\frac{-9+\sqrt{105}}{2} $
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