9x-2(2-3x)=7(9x+2)+7

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Solution for 9x-2(2-3x)=7(9x+2)+7 equation: 



9x-2(2-3x)=7(9x+2)+7

We move all terms to the left:

9x-2(2-3x)-(7(9x+2)+7)=0

We add all the numbers together, and all the variables

9x-2(-3x+2)-(7(9x+2)+7)=0

We multiply parentheses

9x+6x-(7(9x+2)+7)-4=0



We calculate terms in parentheses: -(7(9x+2)+7), so:

7(9x+2)+7

We multiply parentheses

63x+14+7

We add all the numbers together, and all the variables

63x+21

Back to the equation:

-(63x+21)



We add all the numbers together, and all the variables

15x-(63x+21)-4=0

We get rid of parentheses

15x-63x-21-4=0

We add all the numbers together, and all the variables

-48x-25=0

We move all terms containing x to the left, all other terms to the right

-48x=25

x=25/-48

x=-25/48

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