9x-2(4x-3)=16-5(-x+3)-2x

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Solution for 9x-2(4x-3)=16-5(-x+3)-2x equation: 



9x-2(4x-3)=16-5(-x+3)-2x

We move all terms to the left:

9x-2(4x-3)-(16-5(-x+3)-2x)=0

We add all the numbers together, and all the variables

9x-2(4x-3)-(16-5(-1x+3)-2x)=0

We multiply parentheses

9x-8x-(16-5(-1x+3)-2x)+6=0



We calculate terms in parentheses: -(16-5(-1x+3)-2x), so:

16-5(-1x+3)-2x

determiningTheFunctionDomain
-5(-1x+3)-2x+16

We add all the numbers together, and all the variables

-2x-5(-1x+3)+16

We multiply parentheses

-2x+5x-15+16

We add all the numbers together, and all the variables

3x+1

Back to the equation:

-(3x+1)



We add all the numbers together, and all the variables

x-(3x+1)+6=0

We get rid of parentheses

x-3x-1+6=0

We add all the numbers together, and all the variables

-2x+5=0

We move all terms containing x to the left, all other terms to the right

-2x=-5

x=-5/-2

x=2+1/2

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