9x-2(x+5)=5(x+6x-5(2x))

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Solution for 9x-2(x+5)=5(x+6x-5(2x)) equation: 



9x-2(x+5)=5(x+6x-5(2x))

We move all terms to the left:

9x-2(x+5)-(5(x+6x-5(2x)))=0

We add all the numbers together, and all the variables

9x-2(x+5)-(5(-45x))=0

We multiply parentheses

9x-2x-(5(-45x))-10=0



We calculate terms in parentheses: -(5(-45x)), so:

5(-45x)

We multiply parentheses

-225x

Back to the equation:

-(-225x)



We add all the numbers together, and all the variables

7x-(-225x)-10=0

We get rid of parentheses

7x+225x-10=0

We add all the numbers together, and all the variables

232x-10=0

We move all terms containing x to the left, all other terms to the right

232x=10

x=10/232

x=5/116

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