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9x-2(x-3)=7(x+1)+5
We move all terms to the left:
9x-2(x-3)-(7(x+1)+5)=0
We multiply parentheses
9x-2x-(7(x+1)+5)+6=0
We calculate terms in parentheses: -(7(x+1)+5), so:We add all the numbers together, and all the variables
7(x+1)+5
We multiply parentheses
7x+7+5
We add all the numbers together, and all the variables
7x+12
Back to the equation:
-(7x+12)
7x-(7x+12)+6=0
We get rid of parentheses
7x-7x-12+6=0
We add all the numbers together, and all the variables
-6!=0
There is no solution for this equation
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