9x-2(x-3)=7(x+1)+7

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Solution for 9x-2(x-3)=7(x+1)+7 equation: 



9x-2(x-3)=7(x+1)+7

We move all terms to the left:

9x-2(x-3)-(7(x+1)+7)=0

We multiply parentheses

9x-2x-(7(x+1)+7)+6=0



We calculate terms in parentheses: -(7(x+1)+7), so:

7(x+1)+7

We multiply parentheses

7x+7+7

We add all the numbers together, and all the variables

7x+14

Back to the equation:

-(7x+14)



We add all the numbers together, and all the variables

7x-(7x+14)+6=0

We get rid of parentheses

7x-7x-14+6=0

We add all the numbers together, and all the variables

-8!=0

There is no solution for this equation

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