9x-2(x-3)=7(x+1)5

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Solution for 9x-2(x-3)=7(x+1)5 equation: 



9x-2(x-3)=7(x+1)5

We move all terms to the left:

9x-2(x-3)-(7(x+1)5)=0

We multiply parentheses

9x-2x-(7(x+1)5)+6=0



We calculate terms in parentheses: -(7(x+1)5), so:

7(x+1)5

We multiply parentheses

35x+35

Back to the equation:

-(35x+35)



We add all the numbers together, and all the variables

7x-(35x+35)+6=0

We get rid of parentheses

7x-35x-35+6=0

We add all the numbers together, and all the variables

-28x-29=0

We move all terms containing x to the left, all other terms to the right

-28x=29

x=29/-28

x=-1+1/28

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