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9x-3(2x-10)=6(8-x)
We move all terms to the left:
9x-3(2x-10)-(6(8-x))=0
We add all the numbers together, and all the variables
9x-3(2x-10)-(6(-1x+8))=0
We multiply parentheses
9x-6x-(6(-1x+8))+30=0
We calculate terms in parentheses: -(6(-1x+8)), so:We add all the numbers together, and all the variables
6(-1x+8)
We multiply parentheses
-6x+48
Back to the equation:
-(-6x+48)
3x-(-6x+48)+30=0
We get rid of parentheses
3x+6x-48+30=0
We add all the numbers together, and all the variables
9x-18=0
We move all terms containing x to the left, all other terms to the right
9x=18
x=18/9
x=2
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