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9x-3(x-2)=3(2x+3)
We move all terms to the left:
9x-3(x-2)-(3(2x+3))=0
We multiply parentheses
9x-3x-(3(2x+3))+6=0
We calculate terms in parentheses: -(3(2x+3)), so:We add all the numbers together, and all the variables
3(2x+3)
We multiply parentheses
6x+9
Back to the equation:
-(6x+9)
6x-(6x+9)+6=0
We get rid of parentheses
6x-6x-9+6=0
We add all the numbers together, and all the variables
-3!=0
There is no solution for this equation
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