9x-3(x-4)=5(x+4)

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Solution for 9x-3(x-4)=5(x+4) equation: 



9x-3(x-4)=5(x+4)

We move all terms to the left:

9x-3(x-4)-(5(x+4))=0

We multiply parentheses

9x-3x-(5(x+4))+12=0



We calculate terms in parentheses: -(5(x+4)), so:

5(x+4)

We multiply parentheses

5x+20

Back to the equation:

-(5x+20)



We add all the numbers together, and all the variables

6x-(5x+20)+12=0

We get rid of parentheses

6x-5x-20+12=0

We add all the numbers together, and all the variables

x-8=0

We move all terms containing x to the left, all other terms to the right

x=8

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