9x-3(x-5)=2(x+10)

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Solution for 9x-3(x-5)=2(x+10) equation: 



9x-3(x-5)=2(x+10)

We move all terms to the left:

9x-3(x-5)-(2(x+10))=0

We multiply parentheses

9x-3x-(2(x+10))+15=0



We calculate terms in parentheses: -(2(x+10)), so:

2(x+10)

We multiply parentheses

2x+20

Back to the equation:

-(2x+20)



We add all the numbers together, and all the variables

6x-(2x+20)+15=0

We get rid of parentheses

6x-2x-20+15=0

We add all the numbers together, and all the variables

4x-5=0

We move all terms containing x to the left, all other terms to the right

4x=5

x=5/4

x=1+1/4

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