9x-3(x-5)=3(x-4)+5

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Solution for 9x-3(x-5)=3(x-4)+5 equation: 



9x-3(x-5)=3(x-4)+5

We move all terms to the left:

9x-3(x-5)-(3(x-4)+5)=0

We multiply parentheses

9x-3x-(3(x-4)+5)+15=0



We calculate terms in parentheses: -(3(x-4)+5), so:

3(x-4)+5

We multiply parentheses

3x-12+5

We add all the numbers together, and all the variables

3x-7

Back to the equation:

-(3x-7)



We add all the numbers together, and all the variables

6x-(3x-7)+15=0

We get rid of parentheses

6x-3x+7+15=0

We add all the numbers together, and all the variables

3x+22=0

We move all terms containing x to the left, all other terms to the right

3x=-22

x=-22/3

x=-7+1/3

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