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9x-3(x-9)=3(x-5)+5
We move all terms to the left:
9x-3(x-9)-(3(x-5)+5)=0
We multiply parentheses
9x-3x-(3(x-5)+5)+27=0
We calculate terms in parentheses: -(3(x-5)+5), so:We add all the numbers together, and all the variables
3(x-5)+5
We multiply parentheses
3x-15+5
We add all the numbers together, and all the variables
3x-10
Back to the equation:
-(3x-10)
6x-(3x-10)+27=0
We get rid of parentheses
6x-3x+10+27=0
We add all the numbers together, and all the variables
3x+37=0
We move all terms containing x to the left, all other terms to the right
3x=-37
x=-37/3
x=-12+1/3
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