9x-3(x-9)=3(x-5)+6

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Solution for 9x-3(x-9)=3(x-5)+6 equation:



9x-3(x-9)=3(x-5)+6
We move all terms to the left:
9x-3(x-9)-(3(x-5)+6)=0
We multiply parentheses
9x-3x-(3(x-5)+6)+27=0
We calculate terms in parentheses: -(3(x-5)+6), so:
3(x-5)+6
We multiply parentheses
3x-15+6
We add all the numbers together, and all the variables
3x-9
Back to the equation:
-(3x-9)
We add all the numbers together, and all the variables
6x-(3x-9)+27=0
We get rid of parentheses
6x-3x+9+27=0
We add all the numbers together, and all the variables
3x+36=0
We move all terms containing x to the left, all other terms to the right
3x=-36
x=-36/3
x=-12

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