9x-3-2-(x-2)=3(1-x)-2x+7

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Solution for 9x-3-2-(x-2)=3(1-x)-2x+7 equation: 



9x-3-2-(x-2)=3(1-x)-2x+7

We move all terms to the left:

9x-3-2-(x-2)-(3(1-x)-2x+7)=0

We add all the numbers together, and all the variables

9x-(x-2)-(3(-1x+1)-2x+7)-3-2=0

We add all the numbers together, and all the variables

9x-(x-2)-(3(-1x+1)-2x+7)-5=0

We get rid of parentheses

9x-x-(3(-1x+1)-2x+7)+2-5=0



We calculate terms in parentheses: -(3(-1x+1)-2x+7), so:

3(-1x+1)-2x+7

We add all the numbers together, and all the variables

-2x+3(-1x+1)+7

We multiply parentheses

-2x-3x+3+7

We add all the numbers together, and all the variables

-5x+10

Back to the equation:

-(-5x+10)



We add all the numbers together, and all the variables

8x-(-5x+10)-3=0

We get rid of parentheses

8x+5x-10-3=0

We add all the numbers together, and all the variables

13x-13=0

We move all terms containing x to the left, all other terms to the right

13x=13

x=13/13

x=1

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