9x-39+47=3x+10

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Solution for 9x-39+47=3x+10 equation: 



9x-39+47=3x+10

We move all terms to the left:

9x-39+47-(3x+10)=0

We add all the numbers together, and all the variables

9x-(3x+10)+8=0

We get rid of parentheses

9x-3x-10+8=0

We add all the numbers together, and all the variables

6x-2=0

We move all terms containing x to the left, all other terms to the right

6x=2

x=2/6

x=1/3

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