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9x-3=(4x+6)+(3x-3)
We move all terms to the left:
9x-3-((4x+6)+(3x-3))=0
We calculate terms in parentheses: -((4x+6)+(3x-3)), so:We get rid of parentheses
(4x+6)+(3x-3)
We get rid of parentheses
4x+3x+6-3
We add all the numbers together, and all the variables
7x+3
Back to the equation:
-(7x+3)
9x-7x-3-3=0
We add all the numbers together, and all the variables
2x-6=0
We move all terms containing x to the left, all other terms to the right
2x=6
x=6/2
x=3
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