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9x-3x(x=5)=3(x-1)
We move all terms to the left:
9x-3x(x-(5))=0
We multiply parentheses
-3x^2+9x+15x=0
We add all the numbers together, and all the variables
-3x^2+24x=0
a = -3; b = 24; c = 0;
Δ = b2-4ac
Δ = 242-4·(-3)·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-24}{2*-3}=\frac{-48}{-6} =+8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+24}{2*-3}=\frac{0}{-6} =0 $
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