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9x-3x+5(1+2x)=7x+3(x-4)
We move all terms to the left:
9x-3x+5(1+2x)-(7x+3(x-4))=0
We add all the numbers together, and all the variables
9x-3x+5(2x+1)-(7x+3(x-4))=0
We add all the numbers together, and all the variables
6x+5(2x+1)-(7x+3(x-4))=0
We multiply parentheses
6x+10x-(7x+3(x-4))+5=0
We calculate terms in parentheses: -(7x+3(x-4)), so:We add all the numbers together, and all the variables
7x+3(x-4)
We multiply parentheses
7x+3x-12
We add all the numbers together, and all the variables
10x-12
Back to the equation:
-(10x-12)
16x-(10x-12)+5=0
We get rid of parentheses
16x-10x+12+5=0
We add all the numbers together, and all the variables
6x+17=0
We move all terms containing x to the left, all other terms to the right
6x=-17
x=-17/6
x=-2+5/6
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