9x-4(3-5x)=17+10(x-3)

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Solution for 9x-4(3-5x)=17+10(x-3) equation: 



9x-4(3-5x)=17+10(x-3)

We move all terms to the left:

9x-4(3-5x)-(17+10(x-3))=0

We add all the numbers together, and all the variables

9x-4(-5x+3)-(17+10(x-3))=0

We multiply parentheses

9x+20x-(17+10(x-3))-12=0



We calculate terms in parentheses: -(17+10(x-3)), so:

17+10(x-3)

determiningTheFunctionDomain
10(x-3)+17

We multiply parentheses

10x-30+17

We add all the numbers together, and all the variables

10x-13

Back to the equation:

-(10x-13)



We add all the numbers together, and all the variables

29x-(10x-13)-12=0

We get rid of parentheses

29x-10x+13-12=0

We add all the numbers together, and all the variables

19x+1=0

We move all terms containing x to the left, all other terms to the right

19x=-1

x=-1/19

x=-1/19

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