9x-4(x-5)=2(x-3)+5

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Solution for 9x-4(x-5)=2(x-3)+5 equation: 



9x-4(x-5)=2(x-3)+5

We move all terms to the left:

9x-4(x-5)-(2(x-3)+5)=0

We multiply parentheses

9x-4x-(2(x-3)+5)+20=0



We calculate terms in parentheses: -(2(x-3)+5), so:

2(x-3)+5

We multiply parentheses

2x-6+5

We add all the numbers together, and all the variables

2x-1

Back to the equation:

-(2x-1)



We add all the numbers together, and all the variables

5x-(2x-1)+20=0

We get rid of parentheses

5x-2x+1+20=0

We add all the numbers together, and all the variables

3x+21=0

We move all terms containing x to the left, all other terms to the right

3x=-21

x=-21/3

x=-7

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