9x-4(x-5)=3(x+2)

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Solution for 9x-4(x-5)=3(x+2) equation: 



9x-4(x-5)=3(x+2)

We move all terms to the left:

9x-4(x-5)-(3(x+2))=0

We multiply parentheses

9x-4x-(3(x+2))+20=0



We calculate terms in parentheses: -(3(x+2)), so:

3(x+2)

We multiply parentheses

3x+6

Back to the equation:

-(3x+6)



We add all the numbers together, and all the variables

5x-(3x+6)+20=0

We get rid of parentheses

5x-3x-6+20=0

We add all the numbers together, and all the variables

2x+14=0

We move all terms containing x to the left, all other terms to the right

2x=-14

x=-14/2

x=-7

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