9x-4(x-8)=2(x-5)+9

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Solution for 9x-4(x-8)=2(x-5)+9 equation: 



9x-4(x-8)=2(x-5)+9

We move all terms to the left:

9x-4(x-8)-(2(x-5)+9)=0

We multiply parentheses

9x-4x-(2(x-5)+9)+32=0



We calculate terms in parentheses: -(2(x-5)+9), so:

2(x-5)+9

We multiply parentheses

2x-10+9

We add all the numbers together, and all the variables

2x-1

Back to the equation:

-(2x-1)



We add all the numbers together, and all the variables

5x-(2x-1)+32=0

We get rid of parentheses

5x-2x+1+32=0

We add all the numbers together, and all the variables

3x+33=0

We move all terms containing x to the left, all other terms to the right

3x=-33

x=-33/3

x=-11

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