9x-4(x-9)=3(x-1)+8

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Solution for 9x-4(x-9)=3(x-1)+8 equation: 



9x-4(x-9)=3(x-1)+8

We move all terms to the left:

9x-4(x-9)-(3(x-1)+8)=0

We multiply parentheses

9x-4x-(3(x-1)+8)+36=0



We calculate terms in parentheses: -(3(x-1)+8), so:

3(x-1)+8

We multiply parentheses

3x-3+8

We add all the numbers together, and all the variables

3x+5

Back to the equation:

-(3x+5)



We add all the numbers together, and all the variables

5x-(3x+5)+36=0

We get rid of parentheses

5x-3x-5+36=0

We add all the numbers together, and all the variables

2x+31=0

We move all terms containing x to the left, all other terms to the right

2x=-31

x=-31/2

x=-15+1/2

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