9x-4(x-9)=3(x-3)+8

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Solution for 9x-4(x-9)=3(x-3)+8 equation:



9x-4(x-9)=3(x-3)+8
We move all terms to the left:
9x-4(x-9)-(3(x-3)+8)=0
We multiply parentheses
9x-4x-(3(x-3)+8)+36=0
We calculate terms in parentheses: -(3(x-3)+8), so:
3(x-3)+8
We multiply parentheses
3x-9+8
We add all the numbers together, and all the variables
3x-1
Back to the equation:
-(3x-1)
We add all the numbers together, and all the variables
5x-(3x-1)+36=0
We get rid of parentheses
5x-3x+1+36=0
We add all the numbers together, and all the variables
2x+37=0
We move all terms containing x to the left, all other terms to the right
2x=-37
x=-37/2
x=-18+1/2

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