9x-4(x-9)=3(x-5)+3

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Solution for 9x-4(x-9)=3(x-5)+3 equation: 



9x-4(x-9)=3(x-5)+3

We move all terms to the left:

9x-4(x-9)-(3(x-5)+3)=0

We multiply parentheses

9x-4x-(3(x-5)+3)+36=0



We calculate terms in parentheses: -(3(x-5)+3), so:

3(x-5)+3

We multiply parentheses

3x-15+3

We add all the numbers together, and all the variables

3x-12

Back to the equation:

-(3x-12)



We add all the numbers together, and all the variables

5x-(3x-12)+36=0

We get rid of parentheses

5x-3x+12+36=0

We add all the numbers together, and all the variables

2x+48=0

We move all terms containing x to the left, all other terms to the right

2x=-48

x=-48/2

x=-24

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