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9x-4+x-1=5(2x-1)
We move all terms to the left:
9x-4+x-1-(5(2x-1))=0
We add all the numbers together, and all the variables
10x-(5(2x-1))-5=0
We calculate terms in parentheses: -(5(2x-1)), so:We get rid of parentheses
5(2x-1)
We multiply parentheses
10x-5
Back to the equation:
-(10x-5)
10x-10x+5-5=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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