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9x-4=2x(8+4x)+7
We move all terms to the left:
9x-4-(2x(8+4x)+7)=0
We add all the numbers together, and all the variables
9x-(2x(4x+8)+7)-4=0
We calculate terms in parentheses: -(2x(4x+8)+7), so:We get rid of parentheses
2x(4x+8)+7
We multiply parentheses
8x^2+16x+7
Back to the equation:
-(8x^2+16x+7)
-8x^2+9x-16x-7-4=0
We add all the numbers together, and all the variables
-8x^2-7x-11=0
a = -8; b = -7; c = -11;
Δ = b2-4ac
Δ = -72-4·(-8)·(-11)
Δ = -303
Delta is less than zero, so there is no solution for the equation
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