9x-4=3(x-4)+6x+8

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Solution for 9x-4=3(x-4)+6x+8 equation: 



9x-4=3(x-4)+6x+8

We move all terms to the left:

9x-4-(3(x-4)+6x+8)=0



We calculate terms in parentheses: -(3(x-4)+6x+8), so:

3(x-4)+6x+8

We add all the numbers together, and all the variables

6x+3(x-4)+8

We multiply parentheses

6x+3x-12+8

We add all the numbers together, and all the variables

9x-4

Back to the equation:

-(9x-4)



We get rid of parentheses

9x-9x+4-4=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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