9x-5(x-3)=4(4x+5)

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Solution for 9x-5(x-3)=4(4x+5) equation: 



9x-5(x-3)=4(4x+5)

We move all terms to the left:

9x-5(x-3)-(4(4x+5))=0

We multiply parentheses

9x-5x-(4(4x+5))+15=0



We calculate terms in parentheses: -(4(4x+5)), so:

4(4x+5)

We multiply parentheses

16x+20

Back to the equation:

-(16x+20)



We add all the numbers together, and all the variables

4x-(16x+20)+15=0

We get rid of parentheses

4x-16x-20+15=0

We add all the numbers together, and all the variables

-12x-5=0

We move all terms containing x to the left, all other terms to the right

-12x=5

x=5/-12

x=-5/12

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