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9x-5=(7)+(3x+4)
We move all terms to the left:
9x-5-((7)+(3x+4))=0
We calculate terms in parentheses: -(7+(3x+4)), so:We get rid of parentheses
7+(3x+4)
determiningTheFunctionDomain (3x+4)+7
We get rid of parentheses
3x+4+7
We add all the numbers together, and all the variables
3x+11
Back to the equation:
-(3x+11)
9x-3x-11-5=0
We add all the numbers together, and all the variables
6x-16=0
We move all terms containing x to the left, all other terms to the right
6x=16
x=16/6
x=2+2/3
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