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9x-6+6x=3(4x-2)
We move all terms to the left:
9x-6+6x-(3(4x-2))=0
We add all the numbers together, and all the variables
15x-(3(4x-2))-6=0
We calculate terms in parentheses: -(3(4x-2)), so:We get rid of parentheses
3(4x-2)
We multiply parentheses
12x-6
Back to the equation:
-(12x-6)
15x-12x+6-6=0
We add all the numbers together, and all the variables
3x=0
x=0/3
x=0
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