9x-7/(6x+5)=6x-3/4x+2

Solution for 9x-7/(6x+5)=6x-3/4x+2 equation:

9x-7/(6x+5)=6x-3/4x+2

We move all terms to the left:

9x-7/(6x+5)-(6x-3/4x+2)=0


Domain of the equation: (6x+5)!=0

We move all terms containing x to the left, all other terms to the right

6x!=-5

x!=-5/6

x!=-5/6

x∈R



Domain of the equation: 4x+2)!=0

x∈R


We get rid of parentheses

9x-7/(6x+5)-6x+3/4x-2=0

We calculate fractions


9x-6x+(-28x)/(24x^2+20x)+(18x+15)/(24x^2+20x)-2=0

We add all the numbers together, and all the variables

3x+(-28x)/(24x^2+20x)+(18x+15)/(24x^2+20x)-2=0

We multiply all the terms by the denominator


3x*(24x^2+20x)+(-28x)+(18x+15)-2*(24x^2+20x)=0

We multiply parentheses

72x^3+60x^2-48x^2+(-28x)+(18x+15)-40x=0

We get rid of parentheses

72x^3+60x^2-48x^2-28x+18x-40x+15=0

We do not support expression: x^3