9x-8+3(2x+2)=-3(x+4)

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Solution for 9x-8+3(2x+2)=-3(x+4) equation: 



9x-8+3(2x+2)=-3(x+4)

We move all terms to the left:

9x-8+3(2x+2)-(-3(x+4))=0

We multiply parentheses

9x+6x-(-3(x+4))+6-8=0



We calculate terms in parentheses: -(-3(x+4)), so:

-3(x+4)

We multiply parentheses

-3x-12

Back to the equation:

-(-3x-12)



We add all the numbers together, and all the variables

15x-(-3x-12)-2=0

We get rid of parentheses

15x+3x+12-2=0

We add all the numbers together, and all the variables

18x+10=0

We move all terms containing x to the left, all other terms to the right

18x=-10

x=-10/18

x=-5/9

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