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9x-8/2x+5=8
We move all terms to the left:
9x-8/2x+5-(8)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
9x-8/2x-3=0
We multiply all the terms by the denominator
9x*2x-3*2x-8=0
Wy multiply elements
18x^2-6x-8=0
a = 18; b = -6; c = -8;
Δ = b2-4ac
Δ = -62-4·18·(-8)
Δ = 612
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{612}=\sqrt{36*17}=\sqrt{36}*\sqrt{17}=6\sqrt{17}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6\sqrt{17}}{2*18}=\frac{6-6\sqrt{17}}{36} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6\sqrt{17}}{2*18}=\frac{6+6\sqrt{17}}{36} $
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