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9x^2+11x-5=-4x^2
We move all terms to the left:
9x^2+11x-5-(-4x^2)=0
We get rid of parentheses
9x^2+4x^2+11x-5=0
We add all the numbers together, and all the variables
13x^2+11x-5=0
a = 13; b = 11; c = -5;
Δ = b2-4ac
Δ = 112-4·13·(-5)
Δ = 381
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{381}}{2*13}=\frac{-11-\sqrt{381}}{26} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{381}}{2*13}=\frac{-11+\sqrt{381}}{26} $
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