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9x^2+120x-2025=0
a = 9; b = 120; c = -2025;
Δ = b2-4ac
Δ = 1202-4·9·(-2025)
Δ = 87300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{87300}=\sqrt{900*97}=\sqrt{900}*\sqrt{97}=30\sqrt{97}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(120)-30\sqrt{97}}{2*9}=\frac{-120-30\sqrt{97}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(120)+30\sqrt{97}}{2*9}=\frac{-120+30\sqrt{97}}{18} $
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