9x2+12x+3=0

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Solution for 9x2+12x+3=0 equation: 



9x^2+12x+3=0

a = 9; b = 12; c = +3;
Δ = b2-4ac
Δ = 122-4·9·3
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-6}{2*9}=\frac{-18}{18}
=-1
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+6}{2*9}=\frac{-6}{18}
=-1/3
$

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