9x2+15x+4=

Solution for 9x2+15x+4= equation:

9x^2+15x+4=

We move all terms to the left:

9x^2+15x+4-()=0

We add all the numbers together, and all the variables

9x^2+15x=0

a = 9; b = 15; c = 0;
Δ = b2-4ac
Δ = 152-4·9·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15}{2*9}=\frac{-30}{18}
=-1+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15}{2*9}=\frac{0}{18}
=0
$