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9x^2+171x+702=0
a = 9; b = 171; c = +702;
Δ = b2-4ac
Δ = 1712-4·9·702
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3969}=63$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(171)-63}{2*9}=\frac{-234}{18} =-13 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(171)+63}{2*9}=\frac{-108}{18} =-6 $
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