If it's not what You are looking for type in the equation solver your own equation and let us solve it.
9x^2+24x+16=0
a = 9; b = 24; c = +16;
Δ = b2-4ac
Δ = 242-4·9·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-24}{18}=-1+1/3$
| 10x-45=5(x) | | 5.49x7=8×56 | | x+68=5x+32 | | 5/6=5/3x | | 2-5(x-6)=4(7-x)+7 | | 14x-63=7(x) | | –6=k–6 | | 2^-x=8^2x-7/3 | | 6x-(-1x+4)=(x-3)-4(6x-5) | | 2(6-4x)=-2(5x-7) | | 4x+45=+21 | | 8(8-4p)=-3p-23 | | 7/c=28/5 | | 8r-24=-34+6r | | 32x-24=8(x) | | (4x-12)3=180 | | -18x-48=-6(x) | | 4x-12x3=180 | | -2(x+2)=-2x-4 | | -18x-48=-6() | | 2x+5(x-1)=5 | | 6/3x=10 | | 11-1/6n=1/6n-1 | | 12/30=9/x | | Z^5+243i=0 | | -5x+6(1+x)=18+5x | | 18+5x=-5x+6(1+x) | | 30+2x=2x-10 | | x+50=2x+7 | | x+(x-5)=450 | | 2/3x-1=6/7x | | 21=7x+28 |