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9x^2+25x-13946=0
a = 9; b = 25; c = -13946;
Δ = b2-4ac
Δ = 252-4·9·(-13946)
Δ = 502681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{502681}=709$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-709}{2*9}=\frac{-734}{18} =-40+7/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+709}{2*9}=\frac{684}{18} =38 $
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