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9x^2+39x-30=0
a = 9; b = 39; c = -30;
Δ = b2-4ac
Δ = 392-4·9·(-30)
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2601}=51$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(39)-51}{2*9}=\frac{-90}{18} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(39)+51}{2*9}=\frac{12}{18} =2/3 $
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