9x2+45x-54=0

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Solution for 9x2+45x-54=0 equation:



9x^2+45x-54=0
a = 9; b = 45; c = -54;
Δ = b2-4ac
Δ = 452-4·9·(-54)
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3969}=63$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-63}{2*9}=\frac{-108}{18} =-6 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+63}{2*9}=\frac{18}{18} =1 $

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