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9x^2+5=446
We move all terms to the left:
9x^2+5-(446)=0
We add all the numbers together, and all the variables
9x^2-441=0
a = 9; b = 0; c = -441;
Δ = b2-4ac
Δ = 02-4·9·(-441)
Δ = 15876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{15876}=126$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-126}{2*9}=\frac{-126}{18} =-7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+126}{2*9}=\frac{126}{18} =7 $
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