9x2+8x-8=0

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Solution for 9x2+8x-8=0 equation:



9x^2+8x-8=0
a = 9; b = 8; c = -8;
Δ = b2-4ac
Δ = 82-4·9·(-8)
Δ = 352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{352}=\sqrt{16*22}=\sqrt{16}*\sqrt{22}=4\sqrt{22}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4\sqrt{22}}{2*9}=\frac{-8-4\sqrt{22}}{18} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4\sqrt{22}}{2*9}=\frac{-8+4\sqrt{22}}{18} $

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