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9x^2+x-11=0
a = 9; b = 1; c = -11;
Δ = b2-4ac
Δ = 12-4·9·(-11)
Δ = 397
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{397}}{2*9}=\frac{-1-\sqrt{397}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{397}}{2*9}=\frac{-1+\sqrt{397}}{18} $
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