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9x^2-105x+300=0
a = 9; b = -105; c = +300;
Δ = b2-4ac
Δ = -1052-4·9·300
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-105)-15}{2*9}=\frac{90}{18} =5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-105)+15}{2*9}=\frac{120}{18} =6+2/3 $
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